Calculus of variations and optimal control; optimization Classical problems Problem
Minimal surface of revolution
Builds on Integral functional with a Lagrangian densityBeltrami identitySurface areaSurface of revolutionCatenoid
Problem
Let and . Among curves with , and , find one whose surface of revolution about the -axis has the least surface area
Remarks
The Lagrangian does not depend on , so the Beltrami identity gives for a constant . The solutions are the catenaries , and their surfaces of revolution are catenoids. Depending on the positions of the two end points, there are two, one or no catenaries through them. When the end circles are far apart compared with their radii, no catenary joins the points and there is no minimiser among such smooth curves. Then the infimum of is , the area of the two end discs, approached by curves that run close to the axis; this limit is the Goldschmidt solution. For some positions where catenaries do exist, the two discs still have smaller total area than every catenoid through the points, and again no smooth curve attains the infimum.
Reading path
To understand this page from the ground up, read these 12 pages in order. The foundations come first.
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- no evidence level
- Catenoid example
- Euclidean space object
- Euler–Lagrange equation concept
- Function concept
- Integral functional with a Lagrangian density concept
- Parametrised surface concept
- Surface of revolution example
- Function of several variables concept
- Surface area concept
- Partial derivative concept
- Beltrami identity statement
- Minimal surface of revolution problem
Further reading
About this page
| Tag | AEG6QWEFRG |
|---|---|
| URI | m2://AEG6QWEFRG |
| Kind | problem |
| Writing | W0 stub |
| MSC | 49Q05, 49K05, 53A10 |
| Status | This copy of the site has no build data. Run m2 status AEG6QWEFRG. |
| About | Minimal surface |
| Uses | Integral functional with a Lagrangian density, Beltrami identity, Surface area, Surface of revolution, Catenoid |
| Same as |
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