Math 2.0

Commutative algebra Theorem

Remainder theorem

Builds on Division algorithm for polynomialsPolynomial evaluation

Statement

Let RR be a commutative ring, let f∈R[x]f \in R[x] and let c∈Rc \in R. Then the remainder of the division of ff by x−cx - c is the constant polynomial f(c)f(c). That is, there is q∈R[x]q \in R[x] with f=(x−c)q+f(c)f = (x - c) q + f(c).

Remarks

The proof: division by the monic polynomial x−cx - c gives f=(x−c)q+rf = (x - c) q + r with rr a constant. Evaluation at cc gives r=f(c)r = f(c). For example, the remainder of x3−2x+5x^3 - 2x + 5 divided by x−2x - 2 is 23−4+5=92^3 - 4 + 5 = 9.

Reading path

To understand this page from the ground up, read these 9 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Group concept
  2. Ring definition
  3. Polynomial ring definition
  4. Degree of a polynomial definition
  5. Polynomial evaluation definition
  6. Leading coefficient definition
  7. Monic polynomial definition
  8. Division algorithm for polynomials statement
  9. Remainder theorem statement

Where this leads

10 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Polynomial_remainder_theorem, lead section
About this page
Tag0TEDQH56RW
URIm2://0TEDQH56RW
Aliasespolynomial-remainder-theorem
Kindstatement, theorem
WritingW1 stated
MSC13F20
StatusThis copy of the site has no build data. Run m2 status 0TEDQH56RW.
UsesDivision algorithm for polynomials, Polynomial evaluation
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