Math 2.0

Number theory Theorem

Sum of the totient over the divisors

Builds on Euler's totient functionDivisibility

Statement

Let nn be a positive integer. Then ∑d∣nφ(d)=n\sum_{d \mid n} \varphi(d) = n, where the sum runs over the positive divisors dd of nn, and φ\varphi is Euler's totient function.

Remarks

The proof: sort the fractions 1n,2n,…,nn\frac{1}{n}, \frac{2}{n}, \dots, \frac{n}{n} by their denominators in lowest terms. For each divisor dd of nn, exactly φ(d)\varphi(d) of them have the denominator dd. For example, for n=12n = 12: φ(1)+φ(2)+φ(3)+φ(4)+φ(6)+φ(12)=1+1+2+2+2+4=12\varphi(1) + \varphi(2) + \varphi(3) + \varphi(4) + \varphi(6) + \varphi(12) = 1 + 1 + 2 + 2 + 2 + 4 = 12. With the Möbius inversion formula, the result gives φ(n)=∑d∣nμ(d) n/d\varphi(n) = \sum_{d \mid n} \mu(d) \, n / d.

History

Gauss proved this identity in his Disquisitiones Arithmeticae of 1801.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Divisibility definition
  2. Greatest common divisor definition
  3. Coprime integers definition
  4. Euler's totient function definition
  5. Sum of the totient over the divisors statement

Where this leads

1 page builds on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Euler%27s_totient_function, Divisor sum
About this page
Tag09JXE6XMCC
URIm2://09JXE6XMCC
Aliasesgauss-totient-sum
Kindstatement, theorem
WritingW0 stub
MSC11A25
StatusThis copy of the site has no build data. Run m2 status 09JXE6XMCC.
UsesEuler's totient function, Divisibility

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