Theorem on friends and strangers
Builds on Complete graph
Statement
Colour each edge of the complete graph red or blue. Then there are three vertices such that the three edges between them have the same colour.
Remarks
Proof: a vertex has edges, so at least of them have one colour, say blue, by the pigeonhole principle. If an edge between their ends is blue, it closes a blue triangle with . Otherwise these three ends form a red triangle. The number is the least possible: has a colouring with no triangle of one colour. Thus the Ramsey number is .
Reading path
To understand this page from the ground up, read these 2 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Complete graph example
- Theorem on friends and strangers statement
Further reading
About this page
| Tag | 0NYM0ZGAK9 |
|---|---|
| URI | m2://0NYM0ZGAK9 |
| Kind | statement, theorem |
| Writing | W1 stated |
| MSC | 05C55, 05D10 |
| Status | This copy of the site has no build data. Run m2 status 0NYM0ZGAK9. |
| Uses | Complete graph |
| Same as |
Markdown · JSON · Edit on GitHub
What this page needs for W2
- edge about out: the concepts that the statement is about (0 of 1)
- edge proves in: at least one proof node (0 of 1)
- edge instance_of or illustrates in: one example that shows the statement at work (0 of 1)
- explanation L2 (0 of 1)
The writing levels say how complete the text of a page is. They do not measure its truth.
What links here
No page links to this page yet.