Math 2.0

Number theory Congruences Theorem

Chinese remainder theorem

Builds on Congruence modulo nCoprime integers

Statement

Let n1,…,nkn_1, \dots, n_k be positive integers that are pairwise coprime, and let N=n1n2⋯nkN = n_1 n_2 \cdots n_k. Let a1,…,aka_1, \dots, a_k be integers. Then there is an integer xx such that x≡ai(modni)x \equiv a_i \pmod{n_i} for each ii. Two such integers are congruent modulo NN.

Remarks

In the language of rings, the map ℤ/Nℤ→ℤ/n1ℤ×⋯×ℤ/nkℤ\mathbb{Z}/N\mathbb{Z} \to \mathbb{Z}/n_1\mathbb{Z} \times \cdots \times \mathbb{Z}/n_k\mathbb{Z}, x‾↦(x‾,…,x‾)\overline{x} \mapsto (\overline{x}, \dots, \overline{x}), is a ring isomorphism. For two moduli mm and nn, write mu+nv=1m u + n v = 1 with Bézout's identity. Then x=a2mu+a1nvx = a_2 m u + a_1 n v solves x≡a1(modm)x \equiv a_1 \pmod m and x≡a2(modn)x \equiv a_2 \pmod n. The Chinese remainder theorem for non-coprime moduli removes the hypothesis of coprimality.

History

The Chinese book Sunzi Suanjing, from the 5th century, contains the oldest known example of the problem. Qin Jiushao gave a complete method in 1247.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Divisibility definition
  2. Congruence modulo n definition
  3. Greatest common divisor definition
  4. Coprime integers definition
  5. Chinese remainder theorem statement

Where this leads

5 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Chinese_remainder_theorem, Statement
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Kindstatement, theorem
WritingW1 stated
MSC11A07
StatusThis copy of the site has no build data. Run m2 status 0FNN9B4W64.
UsesCongruence modulo n, Coprime integers
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