Derivative of a map into a product
Builds on Fréchet derivative
Statement
Let , and be normed vector spaces over , let be open, and let . Let and be Fréchet differentiable at . Then the map , , is Fréchet differentiable at , and Here has the norm .
Remarks
The converse also holds: if is differentiable at , then so are its two components, because each projection is a bounded linear map. Any norm on that is equivalent to the max norm gives the same derivative. Applied times with , this gives the derivative of a map into R^n by components.
Reading path
To understand this page from the ground up, read these 3 pages in order. The foundations come first.
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- Euclidean space object
- Fréchet derivative definition
- Derivative of a map into a product statement
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Further reading
About this page
| Tag | 0QQMXFTX0A |
|---|---|
| URI | m2://0QQMXFTX0A |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 26B05 |
| Status | This copy of the site has no build data. Run m2 status 0QQMXFTX0A. |
| Uses | Fréchet derivative |
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