Math 2.0

Number theory Divisibility and primes Lemma

Euclid's lemma

Builds on Prime numberDivisibility

Statement

Let pp be a prime number, and let aa and bb be integers. If p∣abp \mid a b, then p∣ap \mid a or p∣bp \mid b.

Remarks

The hypothesis that pp is prime is necessary. For example, 6∣4⋅96 \mid 4 \cdot 9, but 6∤46 \nmid 4 and 6∤96 \nmid 9. A short proof uses Bézout's identity. If p∤ap \nmid a, then gcd⁡(p,a)=1\gcd(p, a) = 1, so px+ay=1p x + a y = 1 for some integers xx and yy. Multiply by bb to see that p∣bp \mid b. The generalized Euclid's lemma replaces the prime pp by an integer that is coprime to aa. The lemma is the main step in the proof of the uniqueness part of the fundamental theorem of arithmetic.

History

The lemma is Proposition 30 of Book VII of the Elements of Euclid.

Reading path

To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Divisibility definition
  2. Prime number definition
  3. Euclid's lemma statement

Where this leads

7 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Euclid%27s_lemma, Formulations
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