Math 2.0

Number theory Proposition

Generalized Euclid's lemma

Builds on Coprime integersDivisibility

Statement

Let nn, aa and bb be integers. If n∣abn \mid a b and nn and aa are coprime, then n∣bn \mid b.

Remarks

When nn is a prime pp and p∤ap \nmid a, then pp and aa are coprime. So this result implies Euclid's lemma. The proof uses Bézout's identity: from nx+ay=1n x + a y = 1 we get b=nbx+abyb = n b x + a b y, and nn divides both terms. For example, 5∣3⋅105 \mid 3 \cdot 10 and gcd⁡(5,3)=1\gcd(5, 3) = 1, so 5∣105 \mid 10.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Divisibility definition
  2. Greatest common divisor definition
  3. Coprime integers definition
  4. Generalized Euclid's lemma statement

Where this leads

1 page builds on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Euclid%27s_lemma, Formulations
About this page
Tag03BAREW1Z5
URIm2://03BAREW1Z5
Kindstatement, proposition
WritingW0 stub
MSC11A05
StatusThis copy of the site has no build data. Run m2 status 03BAREW1Z5.
UsesCoprime integers, Divisibility

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