Generalized Euclid's lemma
Builds on Coprime integersDivisibility
Statement
Let , and be integers. If and and are coprime, then .
Remarks
When is a prime and , then and are coprime. So this result implies Euclid's lemma. The proof uses Bézout's identity: from we get , and divides both terms. For example, and , so .
Reading path
To understand this page from the ground up, read these 4 pages in order. The foundations come first.
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- no evidence level
- Divisibility definition
- Greatest common divisor definition
- Coprime integers definition
- Generalized Euclid's lemma statement
Where this leads
1 page builds on this one.
Further reading
- Web https://en.wikipedia.org/wiki/Euclid%27s_lemma, Formulations
About this page
| Tag | 03BAREW1Z5 |
|---|---|
| URI | m2://03BAREW1Z5 |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 11A05 |
| Status | This copy of the site has no build data. Run m2 status 03BAREW1Z5. |
| Uses | Coprime integers, Divisibility |
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