Commutative algebra Basic notions Theorem
Existence of maximal ideals
Builds on Maximal ideal
Statement
Let be a ring and let be an ideal of with . Then there is a maximal ideal of with . In particular, every nonzero ring has a maximal ideal.
Remarks
The proof uses Zorn's lemma. The union of a chain of proper ideals that contain is again a proper ideal, because it does not contain . The statement for every nonzero ring is equivalent to the axiom of choice, over the other axioms of ZF set theory. The statement holds for left, right and two-sided ideals.
History
Wolfgang Krull proved the theorem in 1929 with transfinite induction.
Reading path
To understand this page from the ground up, read these 5 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Group concept
- Ring definition
- Ideal definition
- Maximal ideal definition
- Existence of maximal ideals statement
Where this leads
1 page builds on this one.
Further reading
- Web https://en.wikipedia.org/wiki/Krull%27s_theorem, lead section
About this page
| Tag | 02HJYT53F7 |
|---|---|
| URI | m2://02HJYT53F7 |
| Aliases | krull-s-theorem |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 13A15 |
| Status | This copy of the site has no build data. Run m2 status 02HJYT53F7. |
| Uses | Maximal ideal |
| Same as |
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