Commutative algebra Proposition
Prime elements are irreducible in an integral domain
Statement
Let be an integral domain and let be a prime element. Then is irreducible.
Remarks
The proof: let . Then , so , say. Write . Then , and cancellation gives , so is a unit. The converse is false in general: in , is irreducible but not prime. In a unique factorization domain, irreducible elements are prime.
Reading path
To understand this page from the ground up, read these 10 pages in order. The foundations come first.
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- Group concept
- Ring definition
- Commutative ring definition
- Unit of a ring definition
- Zero divisor definition
- Divisibility in a commutative ring definition
- Integral domain definition
- Prime element definition
- Irreducible element definition
- Prime elements are irreducible in an integral domain statement
Where this leads
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Further reading
- Web https://en.wikipedia.org/wiki/Prime_element, Irreducible elements
About this page
| Tag | 0F0K8DB9TD |
|---|---|
| URI | m2://0F0K8DB9TD |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 13A05 |
| Status | This copy of the site has no build data. Run m2 status 0F0K8DB9TD. |
| Uses | Prime element, Irreducible element, Integral domain |
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