Math 2.0

Functional analysis Example

Uniform metric on bounded functions

Example

Let SS be a nonempty set. Let B(S)B(S) be the set of bounded functions f ⁣:S→ℝf \colon S \to \mathbb{R}, that is, the functions for which there is a real MM with ∣f(s)∣≤M|f(s)| \le M for all s∈Ss \in S. For f,g∈B(S)f, g \in B(S), let d∞(f,g)=sup⁡s∈S∣f(s)−g(s)∣.d_\infty(f, g) = \sup_{s \in S} |f(s) - g(s)|. Then d∞d_\infty is a metric on B(S)B(S), the uniform metric.

Remarks

The supremum is finite, because ∣f(s)−g(s)∣≤∣f(s)∣+∣g(s)∣|f(s) - g(s)| \le |f(s)| + |g(s)| and both functions are bounded. A sequence (fk)(f_k) converges to ff in this metric if and only if fk→ff_k \to f uniformly on SS. For S={1,…,n}S = \{1, \ldots, n\}, it is the sup metric on R^n. It is d∞(f,g)=∥f−g∥∞d_\infty(f, g) = \|f - g\|_\infty for the sup norm.

Where this leads

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Further reading

  1. Web https://en.wikipedia.org/wiki/Uniform_norm, Uniform metric
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