Math 2.0

Real functions Classical inequalities Theorem

Young's inequality for products

Builds on Inequality of arithmetic and geometric means

Statement

Let p,q>1p, q > 1 be real numbers with 1p+1q=1\frac{1}{p} + \frac{1}{q} = 1. Then for all real a,b≥0a, b \ge 0, ab≤app+bqq.a b \le \frac{a^p}{p} + \frac{b^q}{q}. Equality holds if and only if ap=bqa^p = b^q.

Remarks

It is the weighted AM–GM inequality for the numbers apa^p and bqb^q, with weights 1/p1/p and 1/q1/q. For p=q=2p = q = 2 it is ab≤(a2+b2)/2a b \le (a^2 + b^2)/2. It is the main step in the proof of Hölder's inequality. Mathlib states it as Real.young_inequality.

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Where this leads

17 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Young%27s_inequality_for_products, Standard version for conjugate Hölder exponents
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UsesInequality of arithmetic and geometric means
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