A finite integral domain is a field
Builds on Integral domainField
Statement
Let be an integral domain that has a finite number of elements. Then is a field.
Remarks
The proof: for , the map from to is injective by cancellation. A finite set has no injective map to itself that is not surjective, so for some . A consequence is that is a field for every prime . The hypothesis of finiteness is necessary: is an infinite integral domain that is not a field.
Reading path
To understand this page from the ground up, read these 8 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Unit of a ring definition
- Zero divisor definition
- Field definition
- Integral domain definition
- A finite integral domain is a field statement
Where this leads
1 page builds on this one.
Further reading
About this page
| Tag | 0EBE031B8E |
|---|---|
| URI | m2://0EBE031B8E |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 13G05 |
| Status | This copy of the site has no build data. Run m2 status 0EBE031B8E. |
| Uses | Integral domain, Field |
Markdown · JSON · Edit on GitHub
What this page needs for W1
- an inventory row: the row of the inventory that the node accounts for (0 of 1)
The writing levels say how complete the text of a page is. They do not measure its truth.