Math 2.0

Sequences, series, summability Definition

Absolutely convergent improper integral

Builds on Improper integral

Definition

Let f ⁣:[a,∞)→ℝf \colon [a, \infty) \to \mathbb{R} be Riemann integrable on [a,b][a, b] for each b>ab > a. The improper integral ∫a∞f(x) dx\int_a^\infty f(x) \, dx converges absolutely if ∫a∞∣f(x)∣ dx\int_a^\infty |f(x)| \, dx converges.

Remarks

An absolutely convergent improper integral converges. The proof uses 0≤f+∣f∣≤2∣f∣0 \le f + |f| \le 2|f| and the comparison test. The converse fails. The Dirichlet integral ∫0∞sin⁡xx dx\int_0^\infty \frac{\sin x}{x} \, dx converges, but not absolutely. A function on [a,∞)[a, \infty) whose improper integral converges absolutely is Lebesgue integrable there. The two integrals agree.

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  1. Limit point of a set definition
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  8. Riemann integrable function definition
  9. Riemann integral definition
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Further reading

  1. Web https://en.wikipedia.org/wiki/Improper_integral, Improper Riemann integrals and Lebesgue integrals
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