Linear and multilinear algebra; matrix theory Proposition
Dimension of the annihilator
Builds on Annihilator of a subspaceDimension
Statement
Let be a field, let be a finite-dimensional vector space over , and let be a subspace of . Then where is the annihilator of .
Remarks
A proof extends a basis of to a basis of . Then the dual basis forms are a basis of . Another proof uses the isomorphism . With the double dual isomorphism, it gives in finite dimensions.
Reading path
To understand this page from the ground up, read these 15 pages in order. The foundations come first.
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- Vector space definition
- Linear combination definition
- Linear map definition
- Linear subspace definition
- Linear independence definition
- Linear form definition
- Linear span definition
- Space of linear maps definition
- Dual space definition
- Spanning set definition
- Basis definition
- Annihilator of a subspace definition
- Finite-dimensional vector space definition
- Dimension definition
- Dimension of the annihilator statement
Further reading
- Web https://en.wikipedia.org/wiki/Dual_space, Quotient spaces and annihilators
About this page
| Tag | 06Q1EFVH0Q |
|---|---|
| URI | m2://06Q1EFVH0Q |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 15A03, 15A04 |
| Status | This copy of the site has no build data. Run m2 status 06Q1EFVH0Q. |
| Uses | Annihilator of a subspace, Dimension |
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