Real functions Riemann and related integrals Theorem
Lebesgue's criterion for Riemann integrability
Statement
Let and let be bounded. Then is Riemann integrable if and only if the set of points where is not continuous has Lebesgue measure zero.
Remarks
A set has measure zero if for each it is covered by countably many open intervals of total length less than . Countable sets have measure zero. So Thomae's function is integrable, and so is each monotone function. The Dirichlet function is discontinuous everywhere, so it is not integrable. Giuseppe Vitali and Henri Lebesgue proved the criterion independently, in 1907.
Reading path
To understand this page from the ground up, read these 8 pages in order. The foundations come first.
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- Limit point of a set definition
- Partition of an interval definition
- Limit of a function definition
- Mesh of a partition definition
- Riemann sum definition
- Continuity at a point definition
- Riemann integrable function definition
- Lebesgue's criterion for Riemann integrability statement
Where this leads
2 pages build on this one.
Further reading
- Web https://en.wikipedia.org/wiki/Riemann_integral, Integrability
About this page
| Tag | 0565EGK6XP |
|---|---|
| URI | m2://0565EGK6XP |
| Aliases | lebesgue-vitali-theorem |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 26A42 |
| Status | This copy of the site has no build data. Run m2 status 0565EGK6XP. |
| Uses | Riemann integrable function, Continuity at a point |
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