Math 2.0

Real functions Proposition

Power rule

Builds on DerivativeProduct rule

Statement

Let n≥1n \ge 1 be a natural number. Then the function x↦xnx \mapsto x^n is differentiable on ℝ\mathbb{R}, and its derivative at xx is nxn−1n x^{n-1}.

Remarks

Induction on nn with the product rule gives (xn+1)′=(xn⋅x)′=nxn−1⋅x+xn=(n+1)xn(x^{n+1})' = (x^n \cdot x)' = n x^{n-1} \cdot x + x^n = (n + 1) x^n. The same formula holds for negative integers nn when x≠0x \ne 0, and for real exponents when x>0x > 0. Mathlib states it as hasDerivAt_pow.

Reading path

To understand this page from the ground up, read these 8 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Limit point of a set definition
  2. Limit of a function definition
  3. Continuity at a point definition
  4. Derivative definition
  5. Differentiable function definition
  6. Differentiable functions are continuous statement
  7. Product rule statement
  8. Power rule statement

Where this leads

3 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Power_rule, Proof by induction (natural numbers)
About this page
Tag0JZGW75C5Z
URIm2://0JZGW75C5Z
Kindstatement, proposition
WritingW1 stated
MSC26A24
StatusThis copy of the site has no build data. Run m2 status 0JZGW75C5Z.
UsesDerivative, Product rule
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