Math 2.0

Real functions Theorem

Mean value inequality

Builds on Differentiable function of several variablesEuclidean space

Statement

Let U⊆ℝnU \subseteq \mathbb{R}^n be open, let f ⁣:U→ℝmf \colon U \to \mathbb{R}^m be differentiable on UU, and let x,y∈Ux, y \in U be points such that the segment [x,y]={x+t(y−x):0≤t≤1}[x, y] = \{x + t (y - x) : 0 \le t \le 1\} lies in UU. Suppose that M≥0M \ge 0 and ∥Df(z)∥≤M\|Df(z)\| \le M for each z∈[x,y]z \in [x, y], where ∥Df(z)∥=sup⁡∥h∥≤1∥Df(z)h∥\|Df(z)\| = \sup_{\|h\| \le 1} \|Df(z) h\| is the operator norm. Then ∥f(y)−f(x)∥≤M ∥y−x∥.\|f(y) - f(x)\| \le M \, \|y - x\|.

Remarks

For m=1m = 1, the inequality follows from the mean value theorem in several variables. For m≥2m \ge 2 there is in general no equality form, but the inequality still holds. A standard proof applies the one-variable mean value theorem to φ(t)=(f(y)−f(x))⋅f(x+t(y−x))\varphi(t) = (f(y) - f(x)) \cdot f(x + t(y - x)). On a convex set C⊆UC \subseteq U with ∥Df∥≤M\|Df\| \le M on CC, the inequality holds for all x,y∈Cx, y \in C, so ff is Lipschitz on C.

Reading path

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  1. Euclidean space object
  2. Function concept
  3. Function of several variables concept
  4. Limit of a function of several variables concept
  5. Differentiable function of several variables definition
  6. Mean value inequality statement

Where this leads

3 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Mean_value_theorem, Mean value inequality
  2. Web https://en.wikipedia.org/wiki/Mean_value_theorem, Mean value theorem for vector-valued functions
About this page
Tag02CYB184RC
URIm2://02CYB184RC
Kindstatement, theorem
WritingW0 stub
MSC26B05
StatusThis copy of the site has no build data. Run m2 status 02CYB184RC.
UsesDifferentiable function of several variables, Euclidean space

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