Functions of a complex variable Geometric function theory Theorem
Riemann mapping theorem
Builds on Holomorphic functionConformal map
Statement
Let be a nonempty open subset of with . Suppose that is simply connected: is connected, and each closed path in can be continuously deformed in to a constant path. Let . Then there is a biholomorphic map from onto , that is, a bijective holomorphic map with a holomorphic inverse. Moreover, for each there is exactly one such with and a positive real number.
Remarks
A biholomorphic map is conformal, so and are conformally equivalent. The case is excluded: a holomorphic map is bounded, so it is constant by Liouville's theorem. The uniqueness follows from the Schwarz lemma. Riemann stated the theorem in his thesis of 1851, and Osgood gave the first rigorous proof in 1900.
Reading path
To understand this page from the ground up, read these 14 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Complex numbers object
- Complex plane concept
- Real numbers object
- Set bounded above definition
- Real and imaginary parts definition
- Conformal map definition
- Supremum definition
- Completeness axiom statement
- Existence of square roots of nonnegative reals statement
- Square root definition
- Modulus of a complex number definition
- Complex differentiability definition
- Holomorphic function definition
- Riemann mapping theorem statement
Where this leads
6 pages build on this one.
Further reading
About this page
| Tag | 02WHMEG5ZR |
|---|---|
| URI | m2://02WHMEG5ZR |
| Aliases | riemann-mapping |
| Kind | statement, theorem |
| Writing | W1 stated |
| MSC | 30C35 |
| Status | This copy of the site has no build data. Run m2 status 02WHMEG5ZR. |
| Uses | Holomorphic function, Conformal map |
| Same as |
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What this page needs for W2
- edge about out: the concepts that the statement is about (0 of 1)
- edge proves in: at least one proof node (0 of 1)
- edge instance_of or illustrates in: one example that shows the statement at work (0 of 1)
- explanation L2 (0 of 1)
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