Classification of complex quadratic forms
Builds on Diagonalisation of a quadratic formRank of a matrix
Statement
Let be a complex vector space of finite dimension , and let be a quadratic form on . Let be the rank of the symmetric matrix of in a basis. Then has a basis such that, for all , So two quadratic forms on are equivalent if and only if their matrices have the same rank.
Remarks
The proof starts from a diagonal form and replaces by for each . The same result holds over every algebraically closed field of characteristic not . Over , this fails: and have the same rank but are not equivalent.
Reading path
To understand this page from the ground up, read these 17 pages in order. The foundations come first.
Show the path as a graph
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- Matrix definition
- Vector space definition
- Bilinear form definition
- Linear combination definition
- Linear subspace definition
- Orthogonal family for a bilinear form definition
- Quadratic form definition
- Linear independence definition
- Linear span definition
- Diagonalisation of a quadratic form statement
- Column space definition
- Spanning set definition
- Basis definition
- Finite-dimensional vector space definition
- Dimension definition
- Rank of a matrix definition
- Classification of complex quadratic forms statement
Further reading
- Web https://en.wikipedia.org/wiki/Quadratic_form, Equivalence of forms
About this page
| Tag | 0CEX9BRXRZ |
|---|---|
| URI | m2://0CEX9BRXRZ |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 11E04, 15A63 |
| Status | This copy of the site has no build data. Run m2 status 0CEX9BRXRZ. |
| Uses | Diagonalisation of a quadratic form, Rank of a matrix |
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