Linear and multilinear algebra; matrix theory Corollary
Distinct eigenvalues imply diagonalisable
Builds on A matrix is diagonalisable iff it has a basis of eigenvectorsEigenvectors with distinct eigenvalues are linearly independent
Statement
Let be a field and let be an matrix over . If has pairwise distinct eigenvalues in , then is diagonalisable over .
Remarks
Eigenvectors for the distinct eigenvalues are linearly independent, so they form a basis of . The converse fails: is diagonal, but it has only one eigenvalue. For example, has eigenvalues and , so it is diagonalisable.
Reading path
To understand this page from the ground up, read these 22 pages in order. The foundations come first.
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- Identity matrix object
- Matrix definition
- Vector space definition
- Matrix multiplication definition
- Square matrix definition
- Linear combination definition
- Linear map definition
- Linear subspace definition
- Invertible matrix definition
- Diagonal matrix definition
- Linear independence definition
- Endomorphism definition
- Linear span definition
- Similar matrices definition
- Eigenvalue definition
- Spanning set definition
- Diagonalisable matrix definition
- Eigenvector definition
- Basis definition
- A matrix is diagonalisable iff it has a basis of eigenvectors statement
- Eigenvectors with distinct eigenvalues are linearly independent statement
- Distinct eigenvalues imply diagonalisable statement
Further reading
- Web https://en.wikipedia.org/wiki/Diagonalizable_matrix, Characterization
About this page
| Tag | 0Y95Z7MT02 |
|---|---|
| URI | m2://0Y95Z7MT02 |
| Kind | statement, corollary |
| Writing | W0 stub |
| MSC | 15A20 |
| Status | This copy of the site has no build data. Run m2 status 0Y95Z7MT02. |
| Uses | A matrix is diagonalisable iff it has a basis of eigenvectors, Eigenvectors with distinct eigenvalues are linearly independent |
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