Linear and multilinear algebra; matrix theory Proposition
Characteristic polynomial does not depend on the basis
Statement
Let be a commutative ring, let be an matrix over , and let be an invertible matrix over . Then the characteristic polynomials of and are equal: So similar matrices have the same characteristic polynomial.
Remarks
The proof is . Hence the characteristic polynomial of a linear map does not depend on the basis. The converse fails: and both have , but they are not similar.
Reading path
To understand this page from the ground up, read these 13 pages in order. The foundations come first.
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- Identity matrix object
- Matrix definition
- Vector space definition
- Matrix multiplication definition
- Square matrix definition
- Linear map definition
- Invertible matrix definition
- Multilinear map definition
- Similar matrices definition
- Alternating multilinear map definition
- Determinant definition
- Characteristic polynomial definition
- Characteristic polynomial does not depend on the basis statement
Further reading
About this page
| Tag | 0TYMASG33Y |
|---|---|
| URI | m2://0TYMASG33Y |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 15A15, 15A18 |
| Status | This copy of the site has no build data. Run m2 status 0TYMASG33Y. |
| Uses | Characteristic polynomial, Similar matrices |
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