Math 2.0

Linear and multilinear algebra; matrix theory Determinants Theorem

Determinant via the Schur complement

Builds on DeterminantBlock matrixInvertible matrix

Statement

Let KK be a commutative ring and let AA be an invertible p×pp \times p matrix over KK. Let BB, CC and DD be matrices over KK of sizes p×qp \times q, q×pq \times p and q×qq \times q. Then det⁡(ABCD)=det⁡A⋅det⁡(D−CA−1B),\det \begin{pmatrix} A & B \\ C & D \end{pmatrix} = \det A \cdot \det(D - C A^{-1} B), where det⁡\det is the determinant. The matrix D−CA−1BD - C A^{-1} B is the Schur complement of AA in the block matrix.

Remarks

The proof factors the block matrix as (I0CA−1I)(AB0D−CA−1B)\begin{pmatrix} I & 0 \\ C A^{-1} & I \end{pmatrix} \begin{pmatrix} A & B \\ 0 & D - C A^{-1} B \end{pmatrix}. Then it uses the rule for block triangular matrices. For p=q=1p = q = 1 and a≠0a \ne 0, it gives det⁡(abcd)=a(d−cb/a)=ad−bc\det \begin{pmatrix} a & b \\ c & d \end{pmatrix} = a(d - cb/a) = ad - bc.

Reading path

To understand this page from the ground up, read these 12 pages in order. The foundations come first.

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  1. Identity matrix object
  2. Matrix definition
  3. Vector space definition
  4. Block matrix definition
  5. Matrix multiplication definition
  6. Square matrix definition
  7. Linear map definition
  8. Invertible matrix definition
  9. Multilinear map definition
  10. Alternating multilinear map definition
  11. Determinant definition
  12. Determinant via the Schur complement statement

Where this leads

1 page builds on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Schur_complement, Properties
About this page
Tag0KA7A4ENVJ
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Kindstatement, theorem
WritingW0 stub
MSC15A15
StatusThis copy of the site has no build data. Run m2 status 0KA7A4ENVJ.
UsesDeterminant, Block matrix, Invertible matrix

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