Field theory and polynomials Proposition
Finite extensions are algebraic
Builds on Finite extensionAlgebraic extension
Statement
Let be a finite extension. Then is algebraic.
Remarks
The proof: let and . The elements are linearly dependent over . A linear dependence gives a nonzero polynomial with root . So every element of has degree at most over . The converse is false, as the algebraic numbers show. An extension generated by finitely many algebraic elements is finite, by the tower law.
Reading path
To understand this page from the ground up, read these 16 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Subring definition
- Unit of a ring definition
- Polynomial evaluation definition
- Field definition
- Root of a polynomial definition
- Subfield definition
- Field extension definition
- Degree of a field extension definition
- Algebraic element definition
- Finite extension definition
- Algebraic extension definition
- Finite extensions are algebraic statement
Where this leads
3 pages build on this one.
Further reading
- Web https://en.wikipedia.org/wiki/Algebraic_extension, Some properties
About this page
| Tag | 0DFYTNZ6AM |
|---|---|
| URI | m2://0DFYTNZ6AM |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 12F05 |
| Status | This copy of the site has no build data. Run m2 status 0DFYTNZ6AM. |
| Uses | Finite extension, Algebraic extension |
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