Field theory and polynomials Theorem
An algebraic extension of an algebraic extension is algebraic
Builds on Algebraic extensionFinite extensions are algebraicTower law
Statement
Let be fields. If and are algebraic, then is algebraic.
Remarks
The proof: let have minimal polynomial over . The field is finite over , and is finite over . By the tower law, is finite, so is algebraic over . Also, if is algebraic, then and are algebraic.
Reading path
To understand this page from the ground up, read these 19 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Subring definition
- Unit of a ring definition
- Polynomial evaluation definition
- Field definition
- Root of a polynomial definition
- Subfield definition
- Field extension definition
- Degree of a field extension definition
- Algebraic element definition
- Intermediate field definition
- Finite extension definition
- Algebraic extension definition
- Tower law statement
- Finite extensions are algebraic statement
- An algebraic extension of an algebraic extension is algebraic statement
Where this leads
1 page builds on this one.
Further reading
About this page
| Tag | 0TPWS0K1BC |
|---|---|
| URI | m2://0TPWS0K1BC |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 12F05 |
| Status | This copy of the site has no build data. Run m2 status 0TPWS0K1BC. |
| Uses | Algebraic extension, Finite extensions are algebraic, Tower law |
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