The algebraic numbers form a field
Builds on Algebraic elementTower lawFinite extensions are algebraicSubfield
Remarks
The proof: if are algebraic over , then is a finite extension of , by the tower law. So , , and for are algebraic, because finite extensions are algebraic. More generally, for every extension , the elements of that are algebraic over form a subfield of . The field is countable and algebraically closed. It is an algebraic closure of .
Reading path
To understand this page from the ground up, read these 19 pages in order. The foundations come first.
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- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Subring definition
- Unit of a ring definition
- Polynomial evaluation definition
- Field definition
- Root of a polynomial definition
- Subfield definition
- Field extension definition
- Degree of a field extension definition
- Algebraic element definition
- Intermediate field definition
- Finite extension definition
- Algebraic extension definition
- Tower law statement
- Finite extensions are algebraic statement
- The algebraic numbers form a field statement
Further reading
About this page
| Tag | 0QFTETCHKB |
|---|---|
| URI | m2://0QFTETCHKB |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 11R04 |
| Status | This copy of the site has no build data. Run m2 status 0QFTETCHKB. |
| Uses | Algebraic element, Tower law, Finite extensions are algebraic, Subfield |
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