Field theory and polynomials Irreducibility Theorem
Reduction modulo p test for irreducibility
Builds on Irreducible polynomialMonic polynomialGauss's lemma
Statement
Let be a monic polynomial and let be a prime number. Let be the polynomial whose coefficients are those of modulo . If is irreducible in , then is irreducible in and in .
Remarks
The proof: a factorisation into monic factors of positive degree gives , with and . Irreducibility in then follows by Gauss's lemma. The converse is false: is irreducible over , but it is reducible modulo every prime. Example: has no root in , so it is irreducible over , and so over .
Reading path
To understand this page from the ground up, read these 24 pages in order. The foundations come first.
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- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Unit of a ring definition
- Zero divisor definition
- Divisibility in a commutative ring definition
- Degree of a polynomial definition
- Field definition
- Integral domain definition
- Associate elements definition
- Leading coefficient definition
- Prime element definition
- Field of fractions definition
- Irreducible element definition
- Greatest common divisor in an integral domain definition
- Monic polynomial definition
- Unique factorisation domain definition
- Irreducible polynomial definition
- Content of a polynomial definition
- Primitive polynomial definition
- Product of primitive polynomials is primitive statement
- Gauss's lemma statement
- Reduction modulo p test for irreducibility statement
Further reading
- Web https://en.wikipedia.org/wiki/Irreducible_polynomial, Over the integers and finite fields
About this page
| Tag | 0KWWEXW0RN |
|---|---|
| URI | m2://0KWWEXW0RN |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 12E05 |
| Status | This copy of the site has no build data. Run m2 status 0KWWEXW0RN. |
| Uses | Irreducible polynomial, Monic polynomial, Gauss's lemma |
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