Commutative algebra Domains and factorization Theorem
Polynomial ring over a UFD is a UFD
Builds on Unique factorisation domainGauss's lemmaPolynomial ring
Statement
Let be a unique factorisation domain. Then the polynomial ring is a unique factorisation domain.
Remarks
The proof uses Gauss's lemma and unique factorisation in , where is the field of fractions of . The irreducible elements of are the irreducible elements of and the primitive polynomials of positive degree that are irreducible in . By induction, is a unique factorisation domain. In particular, and are. These rings are not principal ideal domains: in and in are not principal.
Reading path
To understand this page from the ground up, read these 21 pages in order. The foundations come first.
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- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Unit of a ring definition
- Zero divisor definition
- Divisibility in a commutative ring definition
- Field definition
- Integral domain definition
- Associate elements definition
- Prime element definition
- Field of fractions definition
- Irreducible element definition
- Greatest common divisor in an integral domain definition
- Unique factorisation domain definition
- Irreducible polynomial definition
- Content of a polynomial definition
- Primitive polynomial definition
- Product of primitive polynomials is primitive statement
- Gauss's lemma statement
- Polynomial ring over a UFD is a UFD statement
Where this leads
6 pages build on this one.
Further reading
About this page
| Tag | 0D6KH8Y59N |
|---|---|
| URI | m2://0D6KH8Y59N |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 13F15 |
| Status | This copy of the site has no build data. Run m2 status 0D6KH8Y59N. |
| Uses | Unique factorisation domain, Gauss's lemma, Polynomial ring |
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