Compact subsets of a metric space are bounded
Statement
Let be a metric space and let be a compact subset of . Then is bounded.
Remarks
Proof: if is empty, it is bounded. Otherwise fix . The open balls for cover , so finitely many of them do. The largest of these balls contains . A compact subset of a metric space is also closed, because metric spaces are Hausdorff. The converse fails in general: a closed bounded set need not be compact. With the metric , the real line is closed and bounded, but not compact.
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To understand this page from the ground up, read these 34 pages in order. The foundations come first.
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- Element definition
- Proposition concept
- Real numbers object
- Set definition
- Conjunction definition
- Disjunction definition
- Implication definition
- Predicate definition
- Empty set object
- Family of sets definition
- Ordered pair definition
- Intersection definition
- Union definition
- Existential quantifier definition
- Universal quantifier definition
- Cartesian product definition
- Subset definition
- Union of a family of sets definition
- Uniqueness quantifier definition
- Binary relation definition
- Topological space definition
- Function definition
- Subspace topology definition
- Metric space definition
- Closed ball definition
- Open ball definition
- Bounded set definition
- Metric topology definition
- Open set definition
- Open cover definition
- Compact space definition
- Compact set definition
- Compactness via open covers statement
- Compact subsets of a metric space are bounded statement
Further reading
- Web https://en.wikipedia.org/wiki/Compact_space, Metric spaces
About this page
| Tag | 0R7BTEWCJ2 |
|---|---|
| URI | m2://0R7BTEWCJ2 |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 54E45 |
| Status | This copy of the site has no build data. Run m2 status 0R7BTEWCJ2. |
| Uses | Compactness via open covers, Bounded set, Open ball |
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