Math 2.0

Real functions Classical inequalities Lemma

Grönwall's inequality

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Statement

Let a<ba < b and let II be an interval of the form [a,b][a, b], [a,b)[a, b) or [a,∞)[a, \infty). Let I∘I^\circ be the interior of II. Differential form: let β,u:I→ℝ\beta, u : I \to \mathbb{R} be continuous, let uu be differentiable on I∘I^\circ, and assume u′(t)≤β(t) u(t)u'(t) \le \beta(t)\, u(t) for each t∈I∘t \in I^\circ. Then u(t)≤u(a)exp⁡(∫atβ(s) ds)for each t∈I.u(t) \le u(a) \exp\left( \int_a^t \beta(s)\, ds \right) \quad \text{for each } t \in I. Integral form: let β,u:I→ℝ\beta, u : I \to \mathbb{R} be continuous with β≥0\beta \ge 0, let α:I→ℝ\alpha : I \to \mathbb{R} be non-decreasing, and assume u(t)≤α(t)+∫atβ(s) u(s) dsfor each t∈I.u(t) \le \alpha(t) + \int_a^t \beta(s)\, u(s)\, ds \quad \text{for each } t \in I. Then u(t)≤α(t)exp⁡(∫atβ(s) ds)for each t∈I.u(t) \le \alpha(t) \exp\left( \int_a^t \beta(s)\, ds \right) \quad \text{for each } t \in I.

Remarks

The differential form needs no assumption on the signs of β\beta and uu. Its proof shows that u(t)exp⁡(−∫atβ)u(t) \exp\left(-\int_a^t \beta\right) is non-increasing. The integral form does not need uu to be differentiable. For constant α=0\alpha = 0, the integral form gives u≤0u \le 0. This is the step that proves uniqueness of solutions. A variant with an additional constant term gives the Grönwall bound, and there is a discrete version.

History

The inequality is named after Thomas Hakon Grönwall. He proved it in 1919, in the integral form with constant α\alpha and β\beta. Richard Bellman proved a slightly more general integral form in 1943.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Gr%C3%B6nwall%27s_inequality, Differential form
  2. Web https://en.wikipedia.org/wiki/Gr%C3%B6nwall%27s_inequality, Integral form for continuous functions
About this page
Tag07EJHQYR9A
URIm2://07EJHQYR9A
Aliasesgronwall-lemma, gronwall-bellman-inequality
Kindstatement, lemma
WritingW0 stub
MSC26D10, 34A40
StatusThis copy of the site has no build data. Run m2 status 07EJHQYR9A.
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