Curl of a gradient is zero
Builds on CurlGradientSchwarz's theorem for C^2 functionsConservative vector field
Statement
Let be open, and let be of class . Then
Remarks
Proof: the first component of the curl of is , and this is zero by Schwarz's theorem. The other components are similar. So a conservative vector field is irrotational. This gives a quick test: if at some point, then has no scalar potential. In , the same argument shows for all when with of class . The converse needs a condition on . It holds on convex sets, but not on every open set.
Reading path
To understand this page from the ground up, read these 21 pages in order. The foundations come first.
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- no evidence level
- Euclidean space object
- Function concept
- Fréchet derivative definition
- Function of several variables concept
- Vector-valued function concept
- Limit of a function of several variables concept
- Partial derivative concept
- Continuity in R^n definition
- Differentiable function of several variables definition
- Partial derivative definition
- Gradient definition
- Differentiable on an open set definition
- Higher partial derivatives definition
- Iterated derivative definition
- C^k function characterised by continuous derivatives statement
- Symmetry of second derivatives statement
- Vector field definition
- Schwarz's theorem for C^2 functions statement
- Conservative vector field definition
- Curl definition
- Curl of a gradient is zero statement
Where this leads
5 pages build on this one.
Further reading
- Web https://en.wikipedia.org/wiki/Vector_calculus_identities, Curl of gradient is zero
About this page
| Tag | 0M2JRW1J0N |
|---|---|
| URI | m2://0M2JRW1J0N |
| Aliases | curl-grad-vanishes |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 26B12 |
| Status | This copy of the site has no build data. Run m2 status 0M2JRW1J0N. |
| Uses | Curl, Gradient, Schwarz's theorem for C^2 functions, Conservative vector field |
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